等加速度直線運動 - 運動
By Bethany
at 2013-12-31T00:00
at 2013-12-31T00:00
Table of Contents
題目如下:等加速度直線運動,第3秒內與第4秒內位移為8m與10m則,(1)初速度為多少_______m/s(2)加速度為多少_______m/s2解答為(1):3(m/s)(2):1(m/s2)請問解答是如何解出來?謝謝
Tags:
運動
All Comments
By Liam
at 2014-01-02T10:43
at 2014-01-02T10:43
By Liam
at 2014-01-04T22:17
at 2014-01-04T22:17
By Thomas
at 2014-01-03T02:00
at 2014-01-03T02:00
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