斜面運動+鉛直拋體 - 運動
By Ina
at 2009-08-20T00:00
at 2009-08-20T00:00
Table of Contents
1.在高h處自靜止落下A石同時自地面以V0初速鉛直向上拋出B石求二石欲在空中相遇Vo之條件.解答上寫A向下位移SA=1/2gt^2B向上位移SB=Vot-1/2gt^2h=SA+SBh=Vott=h/Vo但這樣A的g不是以向下為正而B的g向上為正但這樣不是矛盾了嗎2.斜面上某一位置每隔0.1秒釋放一顆小球SAB=15cmSBC=20cm(A,B,C,D高度由上而下)(1)求CD間距離SCD(2)A
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運動
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By Jacky
at 2009-08-22T21:29
at 2009-08-22T21:29
By Queena
at 2009-08-20T02:14
at 2009-08-20T02:14
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